William Lee Irwin III wrote:
On Tue, May 01, 2007 at 05:58:29AM +0200, Andi Kleen wrote:
From: [email protected]
When in PAE mode we require that the user kernel divide to be
on a 1G boundary. The 2G/2G split does not have that property
so require !X86_PAE
Signed-off-by: Eric W. Biederman <[email protected]>
---
arch/i386/Kconfig | 1 +
1 files changed, 1 insertions(+), 0 deletions(-)
What on earth?
config PAGE_OFFSET
hex
default 0xB0000000 if VMSPLIT_3G_OPT
default 0x78000000 if VMSPLIT_2G
default 0x40000000 if VMSPLIT_1G
default 0xC0000000
This appears to have been introduced by:
commit 975b3d3d5b983eb60706d35f0d24cd19f6badabf
Author: Mark Lord <[email protected]>
Date: Wed Feb 1 03:06:11 2006 -0800
[PATCH] VMSPLIT config options
There's some sort of insanity going on here. Since when is 0x78000000
a 2GB/2GB split? Mark, dare I ask what you were thinking? That should
be VMSPLIT_2G_OPT for 2GB laptops analogously to VMSPLIT_3G_OPT, if
nothing else, as it's certainly not 2GB/2GB.
You need to go search the archives and read the *extensive* thread
on this from when it was introduced. Lots of high profile kernel
developers were in on this one.
The idea is really simple: eliminate the need for HIGHMEM
on common machines.
And yes, VMSPLIT_2G really means VMSPLIT_2G_OPT,
in the same way as the (added last) VMSPLIT_3G_OPT flag.
Cheers
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