El Wed, Apr 25, 2007 at 10:36:38AM +0530 Satyam Sharma ha dit:
> Hi Matthias,
>
> On 4/25/07, Robert Hancock <[email protected]> wrote:
> >Matthias Kaehlcke wrote:
> >> El Tue, Apr 24, 2007 at 07:53:04PM +0200 Oliver Neukum ha dit:
> >>
> >>> Am Dienstag, 24. April 2007 19:49 schrieb Matthias Kaehlcke:
> >>>> @@ -1706,7 +1706,7 @@ static int rp_write(struct tty_struct *tty,
> >>>> if (count <= 0 || rocket_paranoia_check(info, "rp_write"))
> >>>> return 0;
> >>>>
> >>>> - down_interruptible(&info->write_sem);
> >>>> + mutex_lock_interruptible(&info->write_mtx);
> >>> This is a bug. It is also present in the current code, but nevertheless
> >>> it is a bug. If you use an interruptible lock, you must be ready to deal
> >>> with interrupts, which are ignored by this code.
> >> [...]
> >> i'm a bit confused now about the interruptible locks, i thought using
> >> them means that the process will be waked up when receiving a
> >> signal. what role are playing interrupts when using interruptible locks?
> >
> >You are correct, interrupts aren't involved. However if the wait is
> >interrupted by a signal, mutex_lock_interruptible will return a nonzero
> >return code which needs to be checked for (and likely -ERESTARTSYS or
> >-EINTR returned), otherwise the code will blindly continue as though it
> >has locked the mutex even though it has not.
>
> Think I'll elaborate Robert's explanation for your benefit :-) Unlike
> mutex_lock() and down() that put the task to TASK_UNINTERRUPTIBLE
> sleep if the lock can't be acquired immediately,
> mutex_lock_interruptible() and down_interruptible() sleep in
> TASK_INTERRUPTIBLE state. So the task _can_ be woken up (without even
> acquiring the lock) by incoming signals. When that happens, we can't
> just blindly go on ... so the return values of the _interruptible()
> versions of the locking functions *must* be checked for success and if
> not, the task should return with error.
>
> Use -ERESTARTSYS if a previous intermediate caller checks this return
> value and tries and restarts the whole operation. If no such previous
> caller exists (and/or introducing it would involve a change in kernel
> behaviour as seen from userspace), you can safely use -EINTR. The goal
> is that userspace must not get to see -ERESTARTSYS.
thanks to both of you for your explications, i think i understand the
problem much better now
--
Matthias Kaehlcke
Linux Application Developer
Barcelona
The assumption that what currently exists must necessarily
exist is the acid that corrodes all visionary thinking
.''`.
using free software / Debian GNU/Linux | http://debian.org : :' :
`. `'`
gpg --keyserver pgp.mit.edu --recv-keys 47D8E5D4 `-
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