Martin Stoilov wrote:
> Olaf Dietsche wrote:
>
>> Martin Stoilov <[email protected]> writes:
>>
>>
>>
>>> The following code in kobject_add
>>> if (!kobj->k_name)
>>> kobj->k_name = kobj->name;
>>> if (!kobj->k_name) {
>>> pr_debug("kobject attempted to be registered with no name!\n");
>>> WARN_ON(1);
>>> return -EINVAL;
>>> }
>>>
>>> doesn't look right to me. The second 'if' statement looks useless after
>>> the assignment in the first one. May be it was meant to be like:
>>> if (!*kobj->k_name)
>>>
>>>
>> The second test is true, if kobj->name is NULL as well.
>>
>>
> And how would that ever be true? kobj->name is a buffer inside kobj:
>
> struct kobject <http://localhost/lxr/http/ident?i=kobject> {
> const char * k_name;
> char name <http://localhost/lxr/http/ident?i=name>[KOBJ_NAME_LEN <http://localhost/lxr/http/ident?i=KOBJ_NAME_LEN>];
>
> kobj->name will not be NULL, even if kobj itself is NULL.
>
Oops, I am sorry for sending badly formated text! Here it is:
I don't understand how would that ever be true? kobj->name is a buffer inside kobj:
struct kobject {
const char * k_name;
char name[KOBJ_NAME_LEN];
kobj->name will not be NULL, even if kobj itself is NULL.
>> Regards, Olaf.
>> -
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>>
>>
>
> -Martin
> -
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