Andi,
Looking a the exit_idle() code:
static void __exit_idle(void)
{
if (read_pda(isidle) == 0)
return;
write_pda(isidle, 0);
atomic_notifier_call_chain(&idle_notifier, IDLE_END, NULL);
}
I am wondering whether you are exposed to a race condition w.r.t. to interrupts.
Supposed you are in idle, you get an interrupt and you execute __exit_idle(), the
test evaluate to false but before you can change the value of isidle, you get
a higher priority interrupt which then also calls __exit_idle(), the test is still
false and you invoke the notifier, when you return from this interrupt you also
clear the isidle, but you call the notifier yet a second time.
I think that isidle needs to be test_and_clear atomically for this to guarantee
only one call the notifier on __exit_idle().
what do you think?
On Sat, Oct 21, 2006 at 03:22:53PM +0200, Andi Kleen wrote:
>
> > I finally found the culprit for this. The current code is wrong for the
> > simple reason that the cpu_idle() function is NOT always the lowest level
> > idle loop function. For enter_idle()/__exit_idle() to work correctly they
> > must be placed in the lowest-level idle loop. The cpu_idle() eventually ends
> > up in the idle() function, but this one may have a loop in it! This is the
> > case when idle()=cpu_default_idle() and idle()=poll_idle(), for instance.
>
> Ah now I remember - i had actually fixed that (it was the cleanup-idle-loops
> patch) that moved the loops one level up. But then I disabled the patch
> at the request of Andrew because it conflicted with some ACPI idle changes.
>
> I'll readd it for .20, then things should be ok.
>
> -Andi
--
-Stephane
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