Re: Hopefully, kmalloc() will always succeed, but if it doesn't then....

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--- Pekka Enberg <[email protected]> wrote:

> On 10/22/06, Amit Choudhary <[email protected]> wrote:
> > So, if memory allocation to 'a' fails, it is going to kfree 'b'. But since 'b'
> > is not initialized, kfree may crash (unless DEBUG is defined).
> >
> > I have seen the same case at many places when allocating in a loop.
> 
> So you found a bug. Why not send a patch to fix it?
> 

Yes, I will send it.

Regards,
Amit


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