On Wednesday October 11, [email protected] wrote:
>
> > > blocking_notifier_call_chain is
> > > down_read(&nh->rwsem);
> > > ret = notifier_call_chain(&nh->head, val, v);
> > > up_read(&nh->rwsem);
> > >
> > > and so holds ->rwsem while calling the callback.
> > > So the locking sequence ends up as:
> > >
> > > down_read(&cpu_chain.rwsem);
> > > mutex_lock(&workqueue_mutex);
> > > up_read(&cpu_chain.rwsem);
> > >
> > > down_read(&cpu_chain.rwsem);
> > > mutex_unlock(&workqueue_mutex);
> > > up_read(&workqueue_mutex);
> > >
> > > and lockdep doesn't seem to like this. It sees workqueue_mutex
> > > claimed while cpu_chain.rwsem is held. and then it sees
> > > cpu_chain.rwsem claimed while workqueue_mutex is held, which looks a
> > > bit like a class ABBA deadlock.
> > > Of course because it is a 'down_read' rather than a 'down', it isn't
> > > really a dead lock.
>
> ok can you explain to me why "down_read" doesn't make this a deadlock
> while "down" would make it a deadlock? I have trouble following your
> reasoning.....
>
> (remember that rwsems are strictly fair)
I see your point.
While thread A holds just workqueue_mutex,
thread B takes cpu_chain.rwsem for read then tries to take
workqueue_mutex and blocks.
Now thread C tries to get a write lock on cpu_chain.rwsem and blocks
as well.
Finally thread A moves on to try to get a read lock on cpu_chain.rwsem
and this blocks because thread C is waiting for a write lock.
So A waits on B and C, C waits on B, B waits on A.
Deadlock.
I guess _cpu_down should
down_read(&cpu_chain.rwsem);
and then call notifier_call_chain multiple times. I wonder if that
would be safe.
Who do we blame this on? Are you still the cpu-hot-plug guy Rusty?
NeilBrown
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