From: Ingo Molnar <[email protected]>
fix multiple conversion bugs in msecs_to_jiffies().
the main problem is that this condition:
if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
overflows if HZ is smaller than 1000!
this change is user-visible: for HZ=250 SUS-compliant poll()-timeout
value of -20 is mistakenly converted to 'immediate timeout'.
(the new dyntick code also triggered this, as it frequently creates
'lagging timer wheel' scenarios.)
Signed-off-by: Ingo Molnar <[email protected]>
Signed-off-by: Thomas Gleixner <[email protected]>
--
kernel/time.c | 43 ++++++++++++++++++++++++++++++++++++++++++-
1 file changed, 42 insertions(+), 1 deletion(-)
Index: linux-2.6.18-mm2/kernel/time.c
===================================================================
--- linux-2.6.18-mm2.orig/kernel/time.c 2006-09-30 01:41:15.000000000 +0200
+++ linux-2.6.18-mm2/kernel/time.c 2006-09-30 01:41:15.000000000 +0200
@@ -500,15 +500,56 @@ unsigned int jiffies_to_usecs(const unsi
}
EXPORT_SYMBOL(jiffies_to_usecs);
+/*
+ * When we convert to jiffies then we interpret incoming values
+ * the following way:
+ *
+ * - negative values mean 'infinite timeout' (MAX_JIFFY_OFFSET)
+ *
+ * - 'too large' values [that would result in larger than
+ * MAX_JIFFY_OFFSET values] mean 'infinite timeout' too.
+ *
+ * - all other values are converted to jiffies by either multiplying
+ * the input value by a factor or dividing it with a factor
+ *
+ * We must also be careful about 32-bit overflows.
+ */
unsigned long msecs_to_jiffies(const unsigned int m)
{
- if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
+ /*
+ * Negative value, means infinite timeout:
+ */
+ if ((int)m < 0)
return MAX_JIFFY_OFFSET;
+
#if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
+ /*
+ * HZ is equal to or smaller than 1000, and 1000 is a nice
+ * round multiple of HZ, divide with the factor between them,
+ * but round upwards:
+ */
return (m + (MSEC_PER_SEC / HZ) - 1) / (MSEC_PER_SEC / HZ);
#elif HZ > MSEC_PER_SEC && !(HZ % MSEC_PER_SEC)
+ /*
+ * HZ is larger than 1000, and HZ is a nice round multiple of
+ * 1000 - simply multiply with the factor between them.
+ *
+ * But first make sure the multiplication result cannot
+ * overflow:
+ */
+ if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
+ return MAX_JIFFY_OFFSET;
+
return m * (HZ / MSEC_PER_SEC);
#else
+ /*
+ * Generic case - multiply, round and divide. But first
+ * check that if we are doing a net multiplication, that
+ * we wouldnt overflow:
+ */
+ if (HZ > MSEC_PER_SEC && m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
+ return MAX_JIFFY_OFFSET;
+
return (m * HZ + MSEC_PER_SEC - 1) / MSEC_PER_SEC;
#endif
}
--
-
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