* Jes Sorensen ([email protected]) wrote:
> If you want to prove people wrong, I suggest you do some real life
> implementation and measure some real workloads with a predefined set of
> tracepoints implemented using kprobes and LTT and show us that the
> benchmark of the user application suffers in a way that can actually be
> measured. Argueing that a syscall takes an extra 50 instructions
> because it's traced using kprobes rather than LTT doesn't mean it
> actually has any real impact.
>
And about those extra cycles.. according to :
Documentation/kprobes.txt
"6. Probe Overhead
On a typical CPU in use in 2005, a kprobe hit takes 0.5 to 1.0
microseconds to process. Specifically, a benchmark that hits the same
probepoint repeatedly, firing a simple handler each time, reports 1-2
million hits per second, depending on the architecture. A jprobe or
return-probe hit typically takes 50-75% longer than a kprobe hit.
When you have a return probe set on a function, adding a kprobe at
the entry to that function adds essentially no overhead.
i386: Intel Pentium M, 1495 MHz, 2957.31 bogomips
k = 0.57 usec; j = 1.00; r = 0.92; kr = 0.99; jr = 1.40
x86_64: AMD Opteron 246, 1994 MHz, 3971.48 bogomips
k = 0.49 usec; j = 0.76; r = 0.80; kr = 0.82; jr = 1.07
ppc64: POWER5 (gr), 1656 MHz (SMT disabled, 1 virtual CPU per physical CPU)
k = 0.77 usec; j = 1.31; r = 1.26; kr = 1.45; jr = 1.99
So, 1 microsecond seems more like 1500-2000 cycles to me, not 50.
Mathieu
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