Balbir Singh wrote:
> Jay Lan wrote:
>> Jay Lan wrote:
>>
>> [snip]
>>
>>>>
>>>>
>>>>> + /* Each process gets a minimum of a half tick cpu time */
>>>>> + if ((stats->ac_utime == 0) && (stats->ac_stime == 0)) {
>>>>> + stats->ac_stime = USEC_PER_TICK/2;
>>>>> + }
>>>>> +
>>>>
>>>>
>>>>
>>>> This is confusing. Half tick does not make any sense from the
>>>> scheduler view point (or am I missing something?), so why
>>>> return half a tick to the user.
>>>
>>>
>>> It must be inherited from old code dated back to Cray UNICOS.
>>> I do not know if bad thing can happen if both utime and stime
>>> are less than 1 usec... I guess not. But i agree that
>>> half a tick does not make sense. To play safe, we can change
>>> it to 1 usec if both utime and stime are sub microsecond.
>>> What do you think?
>>
>> Hi Balbir,
>>
>> I figured this out. The tsk->stime (and utime as well) are
>> charged by 1 tick (or cputime) from the timer interrupt handler
>> through update_process_times->account_{user,system}_time.
>>
>> The clock resolution is a tick. Any short process less than
>> 1 tick will the counter being 0. It can be from 0 to 0.99999...
>> tick. A half tick is the average value.
>>
>
> But the scheduling happens in the granularity of a tick, so the
> minimum each task gets is a tick.
>
>> I think it makes more sense to assign a half tick than assign
>> 1 usec to the stime. What do you think? Certainly the code need
>> better explanation.
>>
>
> Can't we leave these values as zero in case both stime and utime are
> zero.
Yes, i will leave them as zero in this case.
Regards,
- jay
>
>
>> Regards,
>> - jay
>>
>>
>> [snip]
>
>
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