Re: [KJ] [patch] fix common mistake in polling loops

["Darren Jenkins" <darrenrjenkins@gmail.com>]

G'day

On 8/8/06, Pavel Machek <pavel@suse.cz> wrote:
> Hi!
>
> > >> Well, whoever wrote thi has some serious problems (in attitude
> > >> department). *Any* loop you design may take half a minute under
> > >> streange circumstances.
> >
> > 6.
> > common mistake in polling loops [from Linus]:
>
> Yes, Linus was wrong here. Or more precisely, he's right original code
> is broken, but his suggested "fix" is worse than the original.
>
>         unsigned long timeout = jiffies + HZ/2;
>         for (;;) {
>                 if (ready())
>                         return 0;
> [IMAGINE HALF A SECOND DELAY HERE]
>                 if (time_after(timeout, jiffies))
>                         break;
>                 msleep(10);
>         }
>
> Oops.
>
> > >Actually it may be broken, depending on use. In some cases this loop
> > >may want to poll the hardware 50 times, 10msec appart... and your loop
> > >can poll it only once in extreme conditions.
> > >
> > >Actually your loop is totally broken, and may poll only once (without
> > >any delay) and then directly timeout :-P -- that will break _any_
> > >user.
> >
> > The Idea is that we are checking some event in external hardware that
> > we know will complete in a given time (This time is not dependant on
> > system activity but is fixed). After that time if the event has not
> > happened we know something has borked.
>
> But you have to make sure YOU CHECK READY AFTER THE TIMEOUT. Linus'
> code does not do that.
>                                                                 Pavel


Sorry I did not realise that was your problem with the code.
Would it help if we just explicitly added a

if (ready())
       return 0;

after the loop, in the example code? so people wont miss adding
something like that in?

Darren J.
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