> (1) IPI 2, not marked as NMI. This does _not_ call into the do_nmi()
> routine.
>
> People have been telling me (hi, Andi:) that sending interrupt 2 as
> an IPI automatically sends it as an NMI.
I can't remember ever saying that. I said that sending anything with the
NMI bit set will end up at the NMI vector, not the original vector
you specified. Or at least that is what the Intel manual specify.
That is why it is useless to hook the original vector like you did
and add special cases just to get an NMI send with different vector.
-Andi
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