Re: Which process is associated with process ID 0 (swapper)

["Joshua Hudson" <joshudson@gmail.com>]

On 4/20/06, Mikado <mikado4vn@gmail.com> wrote:
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> linux-os (Dick Johnson) wrote:
> > This must be a trick question. Linux is not VAX/VMS. There is no
> > swapper process. Check in /proc. Processes start at 1. Even
> > kernel threads have PIDs greater than 1.
>
> Linux really has swapper process ;)
>
> > Portions of the kernel networking code operate detached. The code
> > gets the CPU from a timer queue or from an interrupt. When an
> > connection is attempted, the process attempting the connection
> > is either waiting, with its CPU time being used, or put to
> > sleep, while the timer queue's CPU time is being used. The
> > SYN/ACK handshake is handled during this time, therefore it
> > is possible to find who is attempting that connection. Netstat
> > gets that information from /proc/net and multiple socket
> > calls.
>
> I'm writing kernel module that hooks into netfilter code. I can catch
> packet's information and its owner process. The first SYN packet of
> handshaking belongs to real user-space socket/process. After timeout,
> several SYN packets are generated by kernel-space swapper process (PID
> 0) Is there anyway to find out the relationship between them in
> _kernel_space_ (module context).
>
I would recommend walking the list of sockets, and see what process(es) own
the socket that is bound to that quad (host IP, port; foreigh IP, port).
A better design might just be to hook connect(), but think hard on that one. If
you do it, your module cannot be removed.
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