How should an application ask for uinput module load?

[Samuel Thibault <samuel.thibault@ens-lyon.org>]

Hi,

Given a freshly booted linux box, hence uinput is not loaded (why would
it be, it doesn't drive any real hardware) ; what is the right way(tm)
for an application to have the uinput module loaded, so that it can open
/dev/input/uinput for emulating keypresses?

- With good-old static /dev, we could just open /dev/input/uinput
  (installed by the distribution), and thanks to a
  alias char-major-10-223 uinput
  line somewhere in /etc/modprobe.d, uinput finally gets auto-loaded.

- With devfs, it doesn't look like it works (/dev/misc/uinput is not
  present and opening it just like if it existed doesn't work). But I
  read in archives that it could be feasible.

- With udev, this just cannot work. As explained in an earlier thread,
  even using a special filesystem that would report the opening attempt
  to udevd wouldn't work fine since udevd takes time for creating the
  device, and hence the original program needs to be notified ; this
  becomes racy.

So what is the correct way to do it? I can see two approaches:

Using modprobe:
- try to use /dev/input/uinput ; if it succeeds, fine.
- else, if errno != ENOENT, fail
- else, (ENOENT)
  - try to call `cat /proc/sys/kernel/modprobe` uinput
  - try to use /dev/input/uinput again ; if it succeeds, fine
    - else, assume that it really wasn't compiled, and hence fail.

Triggering auto-load by creating one's own node.
- try to use /dev/input/uinput ; if it suceeds, fine.
- else, if errno != ENOENT, fail
- else, (ENOENT)
  - mknod /somewhere/safe/uinput c 10 223
  - use /somewhere/safe/uinput ; if it succeeds, fine
    - else, assume that it really wasn't compiled, and hence fail.

I guess the same problem arises for loop devices and all such virtual
devices...

Regards,
Samuel
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