On Wed, 22 Feb 2006, Jan Engelhardt wrote:
> Hello,
>
>
>
> from somewhere in my INBOX, this claim was made:
>
>>> (also note that userland processes can map 0x00000000 and the kernel
>>> would jump to it ...)
>
> In C code:
>
> #include <sys/mman.h>
> #include <sys/ioctl.h>
> #include <fcntl.h>
> #include <stdio.h>
> int main(void) {
> int fd = open("badcode.bin", O_RDONLY);
int fd = open("/dev/mem", O_RDWR);
> mmap(NULL, 4096, PROT_READ | PROT_EXEC, MAP_FIXED, fd, 0);
> }
>
> The mmap() usually succeeds and maps something at address 0x00000000. Now
> what if the kernel would try to execute this (of course badly programmed)
> code in the context of this very process?
>
> int (*callback)(int xyz) = NULL;
> callback();
>
> Would not be the badcode be executed with kernel privileges?
> Jan Engelhardt
> --
No. In your demo code, page 0 gets memory-mapped into user space.
This allows user-mode code to access the first page of memory
and even read/write offset 0, still in user mode, with the
root privs that allowed you access to that page in the
first place. Everything you do, is still in user-mode.
You just own some physical memory that the kernel didn't
care about anyway. FYI, the only "strange" thing is that
you can dereference a NULL pointer without error IFF the
"hint" passed to mmap() was a NULL. Mmap()s failure is
depicted by returning (void *) -1, not (void *) 0, so
a returned pointer value of 0 is perfectly okay and can
be used without a seg-fault. To prevent certain 'C'
runtime library functions from refusing to dereference
the pointer, it is best to give mmap() a "hint" of
some valid pointer value like 0x10000000. That will
prevent it from returning the (perfectly legal) NULL.
Cheers,
Dick Johnson
Penguin : Linux version 2.6.15.4 on an i686 machine (5589.54 BogoMips).
Warning : 98.36% of all statistics are fiction.
_
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