On Wed, 15 Feb 2006, Greg KH wrote:
> > > It would only go on the list if the "put" was the last one. Otherwise
> > > it would not make any sense to put it on any list.
> >
> > There's no way to know whether or not any particular "put" is the last
> > one. So you have to assume they all are.
>
> The underlying kobject can "know" that the put was the last one, and
> handle it differently if needed. Yes, it would not use a kref anymore,
> but that might be needed here.
You would need a kref variant, something which would include room for the
list header and a pointer to the release routine. Okay, that does involve
less time overhead than what I proposed (although the same amount of space
overhead).
Alan Stern
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