This path isn't obvious. It looks as if the kernel will be taking
three args from the user stack, but it only takes one from there.
Signed-off-by: Albert Cahalan <[email protected]>
diff -Naurd old/arch/i386/kernel/vsyscall-sysenter.S new/arch/i386/kernel/vsyscall-sysenter.S
--- old/arch/i386/kernel/vsyscall-sysenter.S 2006-02-10 19:55:27.000000000 -0500
+++ new/arch/i386/kernel/vsyscall-sysenter.S 2006-02-10 20:29:39.000000000 -0500
@@ -7,6 +7,21 @@
* for details.
*/
+/*
+ * The caller puts arg2 in %ecx, which gets pushed. The kernel will use
+ * %ecx itself for arg2. The pushing is because the sysexit instruction
+ * (found in entry.S) requires that we clobber %ecx with the desired %esp.
+ * User code might expect that %ecx is unclobbered though, as it would be
+ * for returning via the iret instruction, so we must push and pop.
+ *
+ * The caller puts arg3 in %edx, which the sysexit instruction requires
+ * for %eip. Thus, exactly as for arg2, we must push and pop.
+ *
+ * Arg6 is different. The caller puts arg6 in %ebp. Since the sysenter
+ * instruction clobbers %esp, the user's %esp won't even survive entry
+ * into the kernel. We store %esp in %ebp. Code in entry.S must fetch
+ * arg6 from the stack.
+ */
.text
.globl __kernel_vsyscall
.type __kernel_vsyscall,@function
-
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