The 64-bit conversion routine to convert 64-bit nsec time to a time spec.
gives an unnormalized result if the value being converted is negative. I
think there are two ways to go about fixing this. Most systems will give a
negative remainder and so need to just normalize. On the other hand, some
systems will use div64 to do the division and, I think, it expects unsigned
numbers. The attached patch uses the conservative approach of expecting the
div to be set up for unsigned numbers.
I came accross this when one of my tests set a time near 1 Jan 1970, i.e. it
is a real problem.
--
George Anzinger [email protected]
HRT (High-res-timers): http://sourceforge.net/projects/high-res-timers/
kernel/time.c | 13 ++++++++-----
1 files changed, 8 insertions(+), 5 deletions(-)
Index: linux-2.6.16-rc/kernel/time.c
===================================================================
--- linux-2.6.16-rc.orig/kernel/time.c
+++ linux-2.6.16-rc/kernel/time.c
@@ -702,16 +702,19 @@ void set_normalized_timespec(struct time
*
* Returns the timespec representation of the nsec parameter.
*/
-inline struct timespec ns_to_timespec(const nsec_t nsec)
+struct timespec ns_to_timespec(const nsec_t nsec)
{
struct timespec ts;
- if (nsec)
+ if (nsec) return (struct timespec){0, 0};
+
+ if (nsec < 0) {
+ ts.tv_sec = div_long_long_rem_signed(-nsec, NSEC_PER_SEC,
+ &ts.tv_nsec);
+ set_normalized_timespec(&ts, -ts.tv_sec, -ts.tv_nsec);
+ } else
ts.tv_sec = div_long_long_rem_signed(nsec, NSEC_PER_SEC,
&ts.tv_nsec);
- else
- ts.tv_sec = ts.tv_nsec = 0;
-
return ts;
}
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