Re: typedefs and structs

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



On Wed, 2005-11-09 at 15:40 -0800, Vadim Lobanov wrote:
> On Thu, 10 Nov 2005, Andreas Schwab wrote:
> 
> > Vadim Lobanov <[email protected]> writes:
> >
> > > However, if the code is as follows:
> > > 	void foo (void) {
> > > 		int myvar = 0;
> > > 		printf("%d\n", myvar);
> > > 		bar(&myvar);
> > > 		printf("%d\n", myvar);
> > > 	}
> > > If bar is declared in _another_ file as
> > > 	void bar (const int * var);
> > > then I think the compiler can validly cache the value of 'myvar' for the
> > > second printf without re-reading it. Correct/incorrect?
> >
> > Incorrect. bar() may cast away const.  In C const does not mean readonly.
> 
> In that case, I stand corrected.
> 
> Is there any real reason to apply const to pointer targets, aside from
> giving yourself a warning in the case you try to write the pointer
> target directly? Seems to be a missed opportunity for optimizations
> where the coder designates that it's okay to do so.

Actually, where are you going to cache it? In a register? but calling
bar() may use that register, so it would be stored on the stack anyway.
I doubt that this is a problem with the compiler, since if bar _is_
small, then myvar is most likely already in the processor's cache to
begin with, so it wouldn't need to go back out to memory, unless it was
modified.

-- Steve


-
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to [email protected]
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/

[Index of Archives]     [Kernel Newbies]     [Netfilter]     [Bugtraq]     [Photo]     [Stuff]     [Gimp]     [Yosemite News]     [MIPS Linux]     [ARM Linux]     [Linux Security]     [Linux RAID]     [Video 4 Linux]     [Linux for the blind]     [Linux Resources]
  Powered by Linux