On Tue, Sep 20, 2005 at 05:32:49PM +0200, Peter Duellings wrote:
> Right. But before Log.Log is called arguments of methods are
> copied on the stack. That means, also the current content of
> errno is copied. And "current" means in that case before the call
> to Log.Log is performed (errno is transferred by value - not by
> reference).
And strerror_r() modifies errno. You can't rely on the order arguments
to functions are evaluated in.
-ben
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