Re: EXPORT_SYMBOL generates "is deprecated" noise

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On Sünndag 07 August 2005 20:26, Martin J. Bligh wrote:
> Oh, I'm being an idiot and looking at the wrong tree. It's __deprecated,
> but I still can't think of a clean way to locally undefine that for
> just EXPORT_SYMBOL.

We could in theory create a new EXPORT_SYMBOL variant that does not
reference the symbol directly. This does a little less compile-time
checks but helps reduce the noise. The big advantage of this
would be that we could once again build kernels with -Werror on
developer machines.

Signed-off-by: Arnd Bergmann <[email protected]>

diff --git a/include/linux/module.h b/include/linux/module.h
--- a/include/linux/module.h
+++ b/include/linux/module.h
@@ -182,21 +182,26 @@ void *__symbol_get_gpl(const char *symbo
 #endif
 
 /* For every exported symbol, place a struct in the __ksymtab section */
-#define __EXPORT_SYMBOL(sym, sec)				\
-	__CRC_SYMBOL(sym, sec)					\
-	static const char __kstrtab_##sym[]			\
+#define __EXPORT_SYMBOL(name, sym, sec)				\
+	__CRC_SYMBOL(name, sec)					\
+	static const char __kstrtab_##name[]			\
 	__attribute__((section("__ksymtab_strings")))		\
-	= MODULE_SYMBOL_PREFIX #sym;                    	\
-	static const struct kernel_symbol __ksymtab_##sym	\
+	= MODULE_SYMBOL_PREFIX #name;                    	\
+	static const struct kernel_symbol __ksymtab_##name	\
 	__attribute_used__					\
 	__attribute__((section("__ksymtab" sec), unused))	\
-	= { (unsigned long)&sym, __kstrtab_##sym }
+	= { (unsigned long)&sym, __kstrtab_##name }
 
 #define EXPORT_SYMBOL(sym)					\
-	__EXPORT_SYMBOL(sym, "")
+	__EXPORT_SYMBOL(sym, sym, "")
 
 #define EXPORT_SYMBOL_GPL(sym)					\
-	__EXPORT_SYMBOL(sym, "_gpl")
+	__EXPORT_SYMBOL(sym, sym, "_gpl")
+
+#define EXPORT_DEPRECATED_SYMBOL(sym)				\
+	extern void __deprecated_ ## sym 			\
+			__attribute__((alias(#sym)));		\
+	__EXPORT_SYMBOL(sym, __deprecated_ ## sym, "_gpl")
 
 #endif
 
-
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