linux 2.6.12.3
net/ipv4/fib_semantics.c:line 679
if (fib_info_cnt >= fib_hash_size) {
unsigned int new_size = fib_hash_size << 1;
struct hlist_head *new_info_hash;
struct hlist_head *new_laddrhash;
unsigned int bytes;
if (!new_size)
new_size = 1;
bytes = new_size * sizeof(struct hlist_head *);
new_info_hash = fib_hash_alloc(bytes);
new_laddrhash = fib_hash_alloc(bytes);
if (!new_info_hash || !new_laddrhash) {
fib_hash_free(new_info_hash, bytes);
fib_hash_free(new_laddrhash, bytes);
} else {
memset(new_info_hash, 0, bytes);
memset(new_laddrhash, 0, bytes);
fib_hash_move(new_info_hash, new_laddrhash,
new_size);
}
if (!fib_hash_size)
goto failure;
}
In fib_hash_move, there is no code call fib_hash_free to release memory
used by old hash table. after call fib_hash_move, fib_info_hash and
fib_info_laddrhash are the new memory addresses , old addresses are
lost. Is this a bug?
thanks
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