On Mon, 20 Jun 2005 [email protected] wrote:
> From: Nishanth Aravamudan <[email protected]>
>
>
>
> Use msleep() instead of schedule_timeout() to guarantee the task
> delays as expected. The current code wishes to sleep for 1 jiffy, but I am not
> sure if this is actually intended, as with the change to HZ=1000, the time
> equivalent of 1 jiffy changed from 10ms to 1ms. I have assumed the former in
> this case; however the patch can be easily changed to assume the latter.
[...]
> @@ -529,10 +530,8 @@ static inline u_char xd_waitport (u_shor
> int success;
>
> xdc_busy = 1;
> - while ((success = ((inb(port) & mask) != flags)) && time_before(jiffies, expiry)) {
> - set_current_state(TASK_UNINTERRUPTIBLE);
> - schedule_timeout(1);
> - }
> + while ((success = ((inb(port) & mask) != flags)) && time_before(jiffies, expiry))
> + msleep(10);
> xdc_busy = 0;
> return (success);
> }
I think it's obvious what this code intends and this makes the function
to busy-loop instead of giving up the CPU friendly. The change makes no
sense -- the code is correct as is.
Maciej
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