jdow wrote:
From: "James Purser" <[email protected]>
while (deflate(&stream, 0) == Z_OK)
- /* nothing */
+ /* nothing */;
stream.next_in = buf;
You guys REALLY do not see the changed semantics here? You are
changing:
while (deflate(&stream, 0) == Z_OK)
stream.next_in = buf;
into
while (deflate(&stream, 0) == Z_OK)
;
/* Then the data itself.. */
stream.next_in = buf;
I suspect the results of that tiny bit of code would be slightly
different, especially if "stream.next_in" is volatile, "buf"
is volatile, or if the assignment to next_in has an effect on
the "deflate" operation.
As I already said, deflate() in this case does only ONE iteration.
stream.avail_in is NOT changed in the loop (except of the deflate()
itself, where it will be set to 0 - provided out buffer have enouth
room). So the whole while loop does only ONE iteration, returning
Z_NEED_DATA or something the next one. So no, the semantics here
(actual semantics) does NOT change.
/mjt
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