Dinakar wrote:
> Since only exclusive cpusets can form a sched domain, this ensures
> that the cpus form a disjoint cover
I don't understand why this is so.
Certainly, the exclusive cpusets do not form a disjoint cover. Not
disjoint, because the top cpuset is exclusive, and overlaps with all
other cpusets. Nor do the other exclusive cpusets, excluding the top,
necessarily form a cover - there might not even be any other such
cpusets.
--
I won't rest till it's the best ...
Programmer, Linux Scalability
Paul Jackson <[email protected]> 1.650.933.1373, 1.925.600.0401
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