On Mar 28, 2005, at 9:39 PM, [email protected] wrote:
On Mar 28, 2005, at 9:39 PM, [email protected] wrote:
I already posted one, posts ago.
[snip]
Imporved version:
[snip]
char *dummy = (char *)malloc(1);
That cast is not supposed to be there, is it? (To pretake it: it's
bad.)
What is so bad about it?
Read the FAQ at http://www.eskimo.com/~scs/C-faq/q7.7.html
Malloc() returns a void*, so casts are superfluous if stdlib.h is
included (as it should be). Hence if one typecasts the result of malloc
in order to suit any particular type, the real bug is probably a
lacking "#iinclude <stdlib.h>", which the cast (effectively) is hiding.
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