Re: securityfs_create_dir strange comment

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On Wed, Feb 21, 2007 at 12:45:40AM +0100, Jan Engelhardt wrote:
> 
> On Feb 20 2007 14:26, Greg KH wrote:
> >On Tue, Feb 20, 2007 at 03:18:49PM -0600, Serge E. Hallyn wrote:
> >> Quoting Jan Engelhardt ([email protected]):
> >> > Hello list,
> >> > 
> >> > 
> >> > in security/inode.c, the comment for securityfs_create_dir() reads:
> >> > 
> >> > 	If securityfs is not enabled in the kernel, the value -ENODEV 
> >> > 	will be returned.  It is not wise to check for this value, but 
> >> > 	rather, check for NULL or !NULL instead as to eliminate the need 
> >> > 	for #ifdef in the calling code.
> >> > 
> >> > What is the actual callee that can return NULL - and what should 
> >> > module_init() of a module return when securityfs_create_dir() returns 
> >> > NULL?
> >> 
> >> Hmm, this came from GregKH.  It does seem based on the code that
> >> checking for -ENODEV is necessary, so I don't understand the comment.
> >
> >If securityfs_create_dir() returns NULL, then something bad happened and
> >your code needs to properly recover from it.
> >
> >Other than that, I don't understand the issue here.
> 
> Consider:
> 
> static __init int mymodule_init(void)
> {
>     struct dentry *de;
>     de = securityfs_create_dir("foobar", NULL);
> 
>     /* case 1 */
>     if(IS_ERR(de))
>         return PTR_ERR(de);
> 
>     /* case 2 */
>     if(de == NULL)
>         return WHAT_HERE; /* -EIO? */
> }
> 
> There are two error cases. One: when the function gives us an error code.
> Two: When it returns NULL, without an error code. This looks bogus to me.
> What error is it, when there is no error? - And what should I return to
> modprobe in that case?

Try this instead:
	if (!de)
		return -ENOMEM;
	if ((IS_ERR(de)) && (PTR_ERR(de) != -ENODEV))
		return PTR_ERR(de);
	return 0;

That should cover everything properly, right?

thanks,

greg k-h
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