On Tue, 09 Jan 2007 16:00:51 PST, Amit Choudhary said: > What did you understand when I wrote that "if you access the same memory again using the variable > 'x"? > > Using variable 'x' means using variable 'x' and not variable 'y'. Right - but in real-world code, 'y' is the actual problem. > Did I ever say that it fixes that kind of bug? The point you're missing is that you're "fixing" a failure mode that in general isn't seen, and ignoring the failure mode that *is* seen. > Dereferencing 'x' means dereferencing 'x' and not dereferencing 'y'. And neither "x" nor "y" is "the set of all still-live pointers to already-freed memory" - which is why your proposal doesn't actually do anything effective.
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