On Dec 29 2006 09:36, Martin Stoilov wrote:
> Olaf Dietsche wrote:
>> Martin Stoilov <[email protected]> writes:
>>
>>> The following code in kobject_add
>>> if (!kobj->k_name)
>>> kobj->k_name = kobj->name;
>>> if (!kobj->k_name) {
>>> pr_debug("kobject attempted to be registered with no name!\n");
>>> WARN_ON(1);
>>> return -EINVAL;
>>> }
>>>
>>> doesn't look right to me. The second 'if' statement looks useless after
>>> the assignment in the first one. May be it was meant to be like:
>>> if (!*kobj->k_name)
>>>
>> The second test is true, if kobj->name is NULL as well.
>
>I don't understand how would that ever be true? kobj->name is a buffer inside kobj:
>
>struct kobject {
> const char * k_name;
> char name[KOBJ_NAME_LEN];
>
>kobj->name will not be NULL, even if kobj itself is NULL.
So you probably found a bug. Maybe this was intended then?
if (!kobj->k_name)
kobj->k_name = kobj->name;
if (*kobj->k_name == '\0') {
pr_debug("kobject attempted to be registered with no name!\n");
WARN_ON(1);
return -EINVAL;
}
-`J'
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