On Monday 17 July 2006 21:57, [email protected] wrote:
> On Mon, 17 Jul 2006 20:53:30 +0200, Andreas Mohr said:
> > Hi all,
> >
>
> > for (i = 0; i < 4; i++) {
> > j = INDEX(i);
> > do {
>
> > if (j < (INDEX(i)) && i < 3)
> > list = varray[i + 1]->vec + (INDEX(i + 1));
> > goto found;
> > } while (j != (INDEX(i)));
> > }
> > found:
>
> > Excuse me, but why do we have a while loop here if the last instruction in
> > the while loop is a straight "goto found"?
>
> Consider if we take the 'goto found' when i==1. We leave not only the do/while
> but also the for loop. A 'continue' instead would leave the do/while and then
> drive the i==2 and subsequent 'for' iterations....
No, it would not. A 'continue' instead of the 'goto found' would
compile to nothing.
Try the following example with and without the 'continue'.
#include <stdio.h>
int main(void)
{
int i, j;
for (i = 0; i < 2; i++) {
j = 0;
do {
printf("i==%d, j==%d\n", i, j);
j++;
/* goto found; */
continue;
} while (j < 2);
}
}
Continue is equal to:
LOOP {
/* foo */
goto continue; /* == continue */
/* foo */
continue:
} LOOP
--
Greetings Michael.
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