Hello,
This is the kernel thread in a module. It gets awakened
to do some work as a result of an interrupt. It does
the right thing and works.
But.... `ps` never shows it using ANY cpu time! I know
that the procedure, read_fifo() takes about 600,000 cpu
clocks, measured with rdtsc, so I would expect that
that time would be visible. Does anybody know how to
make the time that a kernel thread uses, become visible
to `ps` ???
static int32_t local_thread(void *unused)
{
DAEMONIZE; // In config.h
SET_PRIORITY(-19); // In config.h
memcpy(current->comm, task_name, sizeof(task_name));
set_current_state(TASK_INTERRUPTIBLE);
schedule_timeout(0); // Let insmod complete
__asm__ __volatile__("thread:\n.global thread\n");
for(;;)
{
set_current_state(TASK_INTERRUPTIBLE);
if(signal_pending(current))
complete_and_exit(&info->quit, 0);
interruptible_sleep_on(&info->twait);
set_current_state(TASK_RUNNING);
read_fifo();
}
return 0; // Just quiet the compiler
}
Cheers,
Dick Johnson
Penguin : Linux version 2.6.13 on an i686 machine (5589.55 BogoMips).
Warning : 98.36% of all statistics are fiction.
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